14=-3u/u^2

Solution for 14=-3u/u^2 equation:

14=-3u/u^2

We move all terms to the left:

14-(-3u/u^2)=0


Domain of the equation: u^2)!=0

u!=0/1

u!=0

u∈R


We get rid of parentheses

3u/u^2+14=0

We multiply all the terms by the denominator


3u+14*u^2=0

We add all the numbers together, and all the variables

14u^2+3u=0

a = 14; b = 3; c = 0;
Δ = b2-4ac
Δ = 32-4·14·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9}=3$
$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-3}{2*14}=\frac{-6}{28}
=-3/14
$
$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+3}{2*14}=\frac{0}{28}
=0
$